9x^2-20=12x

Solution for 9x^2-20=12x equation:

9x^2-20=12x

We move all terms to the left:

9x^2-20-(12x)=0

a = 9; b = -12; c = -20;
Δ = b2-4ac
Δ = -122-4·9·(-20)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12\sqrt{6}}{2*9}=\frac{12-12\sqrt{6}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12\sqrt{6}}{2*9}=\frac{12+12\sqrt{6}}{18}
$